Please help!! Double points! write the ratios for sin X and cos X (Image attached) Will give BRAINLIEST to the person correct answer and please please show your work :))

Answer:The ratio for sin(X) is [tex]\frac{\sqrt{119} }{12}[/tex]The ratio for cos(X) is [tex]\frac{5}{12}[/tex]Step-by-step explanation:- The ratio of the sine of a right triangle is:[tex]sin(\alpha)=\frac{opposite-side}{hypotenuse}[/tex]Since we need the ratio for angle X, [tex]\alpha =X[/tex]. From the picture we can infer that the opposite side of X is [tex]\sqrt{119}[/tex]. The hypotenuse (the side opposite to the right angle) is 12, so replacing the values: [tex]sin(X)=\frac{\sqrt{119} }{12}[/tex]- The ratio of the cosine is: [tex]cos(\alpha)=\frac{adjacent-side}{hypotenuse}[/tex]Similarly, [tex]\alpha =X[/tex], adjacent side = 5, and hypotenuse = 12, so [tex]cos(X)=\frac{5}{12}[/tex]